extract swagger spec from source code and docstring for a flask app
Project description
# flask-swagger-plus
Extract swagger spec from source code (with `Form` and `Schema` components integrated).
A Simple Example
```python
from flask import Flask, jsonify
from flask.views import MethodView
from flask_swagger_plus import Form, SwaggerResponse, StringField, form, swagger
from marshmallow import Schema, fields
class ParamsForm(Form):
email = StringField()
name = StringField()
class AddressSchema(Schema):
street = fields.Str()
state = fields.Str()
country = fields.Str()
class UserAPI(MethodView):
@ParamsForm
@SwaggerResponse(AddressSchema)
def post(self):
"""
create a new user
---
"""
print(form.email)
print(form.name)
return {
'street': 'street',
'state': 'state',
'country': 'country'
}
app = Flask(__name__)
app.add_url_rule('/users/', view_func=UserAPI.as_view('show_users'))
@app.route('/swagger.json')
def spec():
return jsonify(swagger(app))
if __name__ == '__main__':
app.run(debug=True)
```
**docstring** with _---_ is required as we can thus know if you want to export an api to swagger spec.
It's also available if you prefer to using decorator style router registry.
```python
@app.route('/post_user')
@ParamsForm
@SwaggerResponse(AddressSchema)
def post_user():
"""
create user
---
"""
return {}
```
The json result from `/swagger.json` would like
```
{
"definitions": {
"__main__post:AddressSchema": {
"properties": {
"country": {
"type": "string"
},
"state": {
"type": "string"
},
"street": {
"type": "string"
}
}
}
},
"info": {
"title": "Cool product name",
"version": "0.0.0"
},
"paths": {
"/users/": {
"post": {
"description": "",
"parameters": [
{
"description": "",
"in": "formData",
"name": "email",
"type": "string"
},
{
"description": "",
"in": "formData",
"name": "name",
"type": "string"
}
],
"responses": {
"200": {
"description": "api result",
"schema": {
"$ref": "#/definitions/__main__post:AddressSchema"
}
}
},
"security": [],
"summary": "create a new user",
"tags": [
"__main__"
]
}
}
},
"swagger": "2.0"
}
```
Hope you enjoy it!
Extract swagger spec from source code (with `Form` and `Schema` components integrated).
A Simple Example
```python
from flask import Flask, jsonify
from flask.views import MethodView
from flask_swagger_plus import Form, SwaggerResponse, StringField, form, swagger
from marshmallow import Schema, fields
class ParamsForm(Form):
email = StringField()
name = StringField()
class AddressSchema(Schema):
street = fields.Str()
state = fields.Str()
country = fields.Str()
class UserAPI(MethodView):
@ParamsForm
@SwaggerResponse(AddressSchema)
def post(self):
"""
create a new user
---
"""
print(form.email)
print(form.name)
return {
'street': 'street',
'state': 'state',
'country': 'country'
}
app = Flask(__name__)
app.add_url_rule('/users/', view_func=UserAPI.as_view('show_users'))
@app.route('/swagger.json')
def spec():
return jsonify(swagger(app))
if __name__ == '__main__':
app.run(debug=True)
```
**docstring** with _---_ is required as we can thus know if you want to export an api to swagger spec.
It's also available if you prefer to using decorator style router registry.
```python
@app.route('/post_user')
@ParamsForm
@SwaggerResponse(AddressSchema)
def post_user():
"""
create user
---
"""
return {}
```
The json result from `/swagger.json` would like
```
{
"definitions": {
"__main__post:AddressSchema": {
"properties": {
"country": {
"type": "string"
},
"state": {
"type": "string"
},
"street": {
"type": "string"
}
}
}
},
"info": {
"title": "Cool product name",
"version": "0.0.0"
},
"paths": {
"/users/": {
"post": {
"description": "",
"parameters": [
{
"description": "",
"in": "formData",
"name": "email",
"type": "string"
},
{
"description": "",
"in": "formData",
"name": "name",
"type": "string"
}
],
"responses": {
"200": {
"description": "api result",
"schema": {
"$ref": "#/definitions/__main__post:AddressSchema"
}
}
},
"security": [],
"summary": "create a new user",
"tags": [
"__main__"
]
}
}
},
"swagger": "2.0"
}
```
Hope you enjoy it!
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