the OBSCENE string generation one-liner
Project description
The purpose of the mapjoin function is to have an alternative to str.join that looks more like os.path.join (which takes *args).
mapjoin()
from mapjoin import mapjoin, strjoin
mapjoin('foo', 2) # raise TypeError
mapjoin('foo', 2, sep='_', key=str) # return 'foo_2'
# you can also make mapjoin use your own callback with the key kwarg:
your_formatter = lambda key: str(key) if key else 'Nothin!'
mapjoin('foo', obj, 2, None, sep='\n', key=your_formatter)
strjoin()
strjoin('foo', 2) # 'foo-2'
strjoin('foo', 2, sep='_') # 'foo_2'
But … why ?
Initially, because I make to many mistakes when I write an os.path.join call and then a str.join call in a row:
>>> os.path.join('a', 'b')
'a/b'
# and 2 seconds later i'm doing this:
>>> ' '.join('a', 'b')
TypeError: join() takes exactly one argument (2 given)
# and instead of "just fixit and move on", i decided try to make a joint
But also because I can’t get no satisfaction with my code when it looks like:
readable = ' '.join(map(str, [
'hello',
f'__{name}__',
something,
]))
# or:
def foo():
readable = textwrap.dedent(f'''
hello
__{name}__
''').strip()
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