Programming practice exercises in pattern recognition, written in Python. Ideal for beginner programmers.
Project description
programmedpatterns
Practice exercises in pattern recognition, ideal for beginner and intermediate programmers.
This uses the patterns at https://www.visualpatterns.org/ by Fawn Nguyen. The site and this module are licensed under a Creative Commons Attribution license.
The patterns are not in order of difficulty. Many are simple, some are incredibly hard.
THIS MODULE IS CURRENTLY UNDER CONSTRUCTION AND NOT WORKING YET.
Installation
To install with pip, from the Command Prompt/terminal run:
python -m pip install programmedpatterns
Solving the Programming Exercises
After installing, you can find the 461 programming exercises by calling progpat.exercise(X)
where X is 1 to 461. For example:
>>> import progpat
>>> progpat.exercise(1)
Exercise #1
1 2 3 4 5 6 7 8
O OO OOO OOOO OOOOO OOOOOO OOOOOOO OOOOOOOO
OO OOO OOOO OOOOO OOOOOO OOOOOOO OOOOOOOO
OOO OOOO OOOOO OOOOOO OOOOOOO OOOOOOOO
OOOO OOOOO OOOOOO OOOOOOO OOOOOOOO
OOOOO OOOOOO OOOOOOO OOOOOOOO
OOOOOO OOOOOOO OOOOOOOO
OOOOOOO OOOOOOOO
OOOOOOOO
Number of Os:
1 4 9 16 25 36 49 64
Each exercise has a visual string component and a numeric math component. To solve the exercise you must write two functions. The visual string component function must have a name visX()
where X is the exercise number. The numeric math component functionmust have a name numX()
where X is the exercise number.
For example, vis1(3)
would return the string 'OOO\nOOO\nOOO'
because that is the visual string pattern for step 3 of exercise #1. Meanwhile, num1(3)
should return 9
because that is the numeric math component for step 3 of exercise #1. Your two functions should return the correct answers for any integer (greater than 0) passed to them.
You can identify what you're supposed to count in the string displayed by progpat.exercise()
. For example, exercise #1 asks for the number of Os. Most exercises ask for the number of Os, but some exercises have other characters or ask for a number of line segments.
The visual strings don't have trailing whitespace on their lines. They use period (.) characters instead of spaces to make the spacing easier to count.
To check if your code is correct, run the following from the .py file that contains your visX()
and numX()
functions:
import progpat
progpat.check(1, vis1, num1) # Checks the vis1() and num1() functions for correctness.
Notice that you are passing the functions themselves, not calling them. This is why they don't have the () parentheses after their names.
Eventually, I'd like to make a website to track people's solutions (similar to what Advent of Code does).
Contribute
Currently a lot of basic programming work is needed (in Python and other languages) to make Programmed Patterns work.
First, we need the solutions for all 468 patterns. Each solution is comprised of a visX(n)
function that returns a multiline string for pattern X at iteration n, and a numX(n)
function that returns a numeric count of the number of shapes in pattern X at iteration n.
For example, here's pattern #5 which has a medium level of difficulty:
Pattern #5
1 2 3 4 5 6
.OO ..OOO ...OOOO ....OOOOO .....OOOOOO ......OOOOOOO
O.O ...OO ....OOO .....OOOO ......OOOOO .......OOOOOO
OOO O..OO ....OOO .....OOOO ......OOOOO .......OOOOOO
OOOO O...OOO .....OOOO ......OOOOO .......OOOOOO
OOO OOOOO O....OOOO ......OOOOO .......OOOOOO
OOOO OOOOOO O.....OOOOO .......OOOOOO
OOOO OOOOO OOOOOOO O......OOOOOO
OOOOO OOOOOO OOOOOOOO
OOOOO OOOOOO OOOOOOO
OOOOOO OOOOOOO
OOOOOO OOOOOOO
OOOOOOO
OOOOOOO
Number of Os:
7 15 27 43 63 87
The vis5()
function you write should take an integer n
and return a multiline string for the pattern at iteraton n:
def vis5(n):
result = ''
result += ('.' * n) + ('O' * (n + 1)) + '\n'
for i in range(n - 1):
result += ('.' * (n + 1)) + ('O' * n) + '\n'
result += 'O' + ('.' * n) + ('O' * n) + '\n'
result += 'O' * (n + 2) + '\n'
for i in range(n - 1):
result += 'O' * (n + 1) + '\n'
return result
The num5()
function you write should take an integer n
and return the number of 'O'
characters in the pattern at iteration n:
def num5(n):
return 3 + (2 * ((n + 1) * n))
These functions will be used to check student solutions. Each pattern puzzle has a visual string-manipulation component and a mathematical algebra component. This provides a lot of practice for intermediate-level programmers who have learned language syntax but need to become more skillful at writing code.
Where you can help is by writing the solution functions for the unsolved patterns. Check out https://visualpatterns.org and find a pattern to write function solutions for. To avoid working on patterns that other people may be working on, pick patterns to solve randomly by running random.randint(1, 468)
in Python (or some other random selection method) and then check the GitHub repo to make sure it hasn't already been solved.
The source code file has boilerplate visX()
and numX()
functions that you can fill in with your solution. You can then run _getPatternMultilineString(X, 1, 10)
(where X
is the pattern number) to verify that the solution looks correct for iterations 1 through 10.
While the strings returned by the visX()
functions have multiple lines (that is, they contain \n newline charactrs) each line should remove all trailing whitespace for their canonical answer. For example, this pattern:
O
OO
OOO
....should be represented as 'O\nOO\nOOO'
and not 'O \nOO \nOOO\n'
.
You should also draw each pattern as far up and to the left as possible. For example, pattern #22's 2nd iteration should be 'O\nOO'
and not '\n\nO\nOO'
.
Once you have finished the visual and numeric functions for a pattern and ensured they are correct, add a # DONE
comment to the def
statement for the functions and update the visual function's docstring to the output of getPatternMultilineString(patternNum, 1, endIteration)
, where patternNum is the integer of the pattern number and endIteration is as large of an integer as you can make without the output being wider than about 70 or so characters. (This is usually 3 to 6.) It's important that you use the naming pattern visX()
and numX()
for your solution functions or getPatternMultilineString()
won't work.
Special Case Patterns
Most of the patterns involve a progressive growth of generic shapes which are represented by 'O'
strings. For example:
Pattern #9:
O OO OOO OOOO OOOOO
OO OOO OOOO OOOOO OOOOOO
OOO OOOO OOOOO OOOOOO OOOOOOO
Number of Os:
6 9 12 15 18
Pattern #11:
O O O O O
OO O O O O
OOO O O O
OOOO O O
OOOOO O
OOOOOO
Number of Os:
3 5 7 9 11
Pattern #14:
O O O O O
OOOOOO OOOOOO OOOOOO OOOOOO OOOOOO
OOOOOO OOOOOO OOOOOO OOOOOO
OOOOOO OOOOOO OOOOOO
OOOOOO OOOOOO
OOOOOO
Number of Os:
7 13 19 25 31
But some patterns have multiple kinds of shapes. For example, pattern #15:
Pattern #15
1 2 3 4 5 6
.O .O.O .O.O.O .O.O.O.O .O.O.O.O.O .O.O.O.O.O.O
OXO OXOXO OXOXOXO OXOXOXOXO OXOXOXOXOXO OXOXOXOXOXOXO
.O .O.O .O.O.O .O.O.O.O .O.O.O.O.O .O.O.O.O.O.O
Number of Os, Xs:
(4, 1)(7, 2) (10, 3) (13, 4) (16, 5) (19, 6)
In these cases, other letters such as 'X'
are used in addition to 'O'
for the visual component. For the numerical component, the numX()
function doesn't return a simple integer but a tuple of integers. For pattern #15, the tuple returned is in the format (number of Os, number of Xs)
.
Other patterns have line drawings rather than discreet shapes. For example, pattern #44 looks like this:
Pattern #44
1 2 3
....__ ....__....__ ....__....__....__
.__/##\__ .__/##\__/##\__ .__/##\__/##\__/##\__
/##\##/##\ /##\##/##\##/##\ /##\##/##\##/##\##/##\
\##/..\##/ \##/..\##/..\##/ \##/..\##/..\##/..\##/
/##\__/##\ /##\__/##\__/##\ /##\__/##\__/##\__/##\
\##/##\##/ \##/##\##/##\##/ \##/##\##/##\##/##\##/
...\##/ ...\##/..\##/ ...\##/..\##/..\##/
Number of filled hexagons:
6 10 14
These patterns often use /
, \
, _
, and |
for line-drawing characters. In many programming languages, the \
forward slash must be escaped as \\
when written in string literals in your code. In Python, raw strings are a helpful shortcut that allows you to write forward slashes without escaping them: print(r'Hello\\world')
will print Hello\\world
and not Hello\world
.
However, Python has a slight bug in its language design where \ slashes cannot be the last character in a raw string. The code print(r'\Hello\')
produces a syntax error instead of displaying \Hello\
. You cannot use raw strings in these cases and instead must use normal strings with escape characters: print('\\Hello\\')
Please contact me at al@inventwithpython.com or on Twitter @AlSweigart if you'd like to contribute to this git repo.
How to Solve Programmed Patterns
TODO - Finish this section with advice on how to tackle these problems. (i.e. notice the changes between iterations including amounts, recall that you'll print things left-to-right, break it down line by line, use loops for multiple lines and string replication for multiple characters on a line, etc.)
Support
If you find this project helpful and would like to support its development, consider donating to its creator on Patreon.
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